By Ajay Kumar

Verified by Ajay Kumar

A number when divided by 45 leaves remainder 27, and when divided by 27 leaves remainder 9. Find the smallest such number.

  1. 189

  2. 117

  3. 369

  4. 459

Answer: B

Solution

Check 117: \(117=45\times2+27\), so the remainder is 27 when divided by 45. Also, \(117=27\times4+9\), so the remainder is 9 when divided by 27. Therefore, the smallest such number is 117. Trick: Check the given options against both remainder conditions.

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